Recursive function on sublist returning None

Question

I\'m running a recursive function on sublist to search the element check_value in the list once it finds it, it verifies whether other_value is the first item of the correspondi

Answer 1

def check_with_list(dd, check_value, other_value=None):
        global new_index
    for index, h in enumerate(dd):
        if isinstance(h, list):
            result = check_with_list(h, check_value)

            if result is not None:
                if other_value:
                    new = (index,) + result
                    if len(new) == 2:

                        if dd[new[0]][0] == other_value:
                            result = None
                        else:
                            return (index,) + result


        elif h == check_value:
            return (index,)
    # value not found
    return None


dd = [
    "gcc",
    "fcc",
    ["scc", "jhh", "rrr"],
    ["www", "rrr", "rrr"],
    "mmm",
    ["qwe", ["ree", "rrr", "rrr"], "ere"]
]
dd = check_with_list(dd, "rrr", "ree")

I have removed the not from the line below:

if not dd[new[0]][0] == other_value:

Everything else seems to be perfect. The code works and returns the index of the 1st occurrence of check_value in dd.