C: Behaviour of arrays when assigned to pointers

Question

#include 

main()
{
  char * ptr;

  ptr = \"hello\";


  printf(\"%p %s\" ,\"hello\",ptr );

  getchar();

}

Hi, I am trying to underst

Answer 1

#include 

main()
{
   char * ptr;

   ptr = "hello"; 

  //instead of above tow lines you can write char *ptr = "hello" 

   printf("%p %s" ,"hello",ptr );

   getchar();

}

Here you have assigned string literal "hello" to ptr it means string literal is stored in read only memory so you can't modify it. If you declare char ptr[] = "hello";, then you can modify the array.