Create a random number and check if it is odd or even

Question

I am looking to create a batch file that, when ran, creates a random integer from 0 to 100 and then runs it through an if statement that checks whether it is odd or even. I\'ve

Answer 1

The following prints a random number between 0 and 99, and prints whether it's even or odd:

@echo off

set /a num = %random% %% 100
echo %num%
set /a odd = num %% 2
if %odd% EQU 1 (echo odd) else (echo even)