ostream cout and char *

Question

I have an array of chars like this one:

char arr[3]=\"hi\";
cout << arr;// this will print out hi

So is the operator<< has an

Answer 1

Exactly in the same way as cout works.

The array arr decays into pointer type, and there exists an overloaded version of istream as well which takes char* as argument. So arr gets passed to the operator>> as char* after decaying.