Explain output of this C program

Question

Found this code at C Puzzles.

#include

int main()
{
  int a=1;
  switch(a)
  {   int b=20;
      case 1: printf(\"b is %d\\n\",b);
                       


        

Answer 1

#include
int main()
{
    int a = 1;
    switch(a) {   
        int b=20;
        printf("This gets called!\n");
        case 1: 
                printf("b is %d\n",b);
                break;
        default:
                printf("b is %d\n",b);
                break;
    }
    return 0;
}

The key here is that int b=20; never gets called. The compiler will create the variable b but it never gets initialised.