SQL and PHP filter

Question

I have a SQL table with model year from and model year to, in filter I need to select only one parameter year and I want to get all models which are in that year gap.

Answer 1

Seem like you don't have put the full request, but you should be able to do something with this :

WHERE
    $year >= `from`
    AND $year <= coalesce(`to`, 9999)

The coalesce() is here in case you don't have a to date but a NULL instead (still in production).

---

Here is the full version : (As I really can't stand mysqli_* function, and they are not well suited/secure for this use case, This is a PDO solution)

setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_OBJ); 
        // error SQL as object
    $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
    $db->exec("SET CHARACTER SET utf8");

} catch (Exception $e) {
    echo ''.$e->getMessage().'
'."\n";
}
    // default parameters
$param = array();
$sql = "SELECT * FROM `cars` WHERE `id` != '' ";

if(!empty($_POST['make'])){
    $param[':make'] = $_POST['make'];
    $sql .= 'AND `make` = :make ';
}

if(!empty($_POST['model'])){
    $param[':model'] = $_POST['model'];
    $sql .= 'AND `model` = :model ';
}

if(!empty($_POST['from'])){
    $param[':from'] = $_POST['from'];
    $sql .= 'AND :from >= coalesce(`from`, 0) AND :from <= coalesce(`to`, 9999) ';
}

    // we prepare our request
$stmt = $db->prepare($sql);
    // we execute with our parameters
$stmt->execute($param);

while($r = $stmt->fetch()){
    echo $r->id.' - '.$r->make.' - '.$r->model.' - '.$r->from;
    echo"
";
}