How to save multiple $! into variables and use it later in bash?

Question

I want to get the pids of two background processes,

sleep 20 & pid1=$\\!; sleep 10 & pid2=$\\!; echo \"pid1: $pid1, pid2: $pid2\"

and

Answer 1

Your syntax kindly incorrect, try this:

[root@XXX ~]# sleep 5 & pid1=$!; sleep 6 & pid2=$!; echo "pid1: ${pid1}, pid2: ${pid2}"
[1] 2308
[2] 2309
pid1: 2308, pid2: 2309