Shuffle array in Unity

Question

I want to shuffle the numbers in my array variable once, so I called my Shuffle method from Start().

I then attempt access the sh

Answer 1

Move int[] array = { 1, 2, 3, 4, 5, 6, 7, 8}; outside the Start function.

private System.Random _random = new System.Random();
float sec;
float timecount;
float starttime;

int[] array = { 1, 2, 3, 4, 5, 6, 7, 8 };

void Start()
{
    starttime = Time.time;
    Shuffle(array);
    foreach (int value in array)
    {
        Debug.Log(value);
    }
}

void Update()
{
    //time
    timecount = Time.time - starttime;
    sec = (timecount % 60f);
    if (Mathf.Round(sec) == 3f)
    {
        //access shuffled array
        Debug.Log(array[3]);
    }
}

//for shuffle number from array
void Shuffle(int[] array)
{
    int p = array.Length;
    for (int n = p - 1; n > 0; n--)
    {
        int r = _random.Next(0, n);
        int t = array[r];
        array[r] = array[n];
        array[n] = t;
    }
}

EDIT: Not related to your question.

There is a bug in your Shuffle function. array[0] will always remain 1 and will never change. To fix this, replace int r = _random.Next(1, n); with int r = _random.Next(0, n); in the Shuffle function.