sort a list of dictionary by taking integer value of keys stored as string

Question

I have a list of dictionaries with values stored as strings. I want to sort them by taking the values as integer not string. Code I have

 XWordDict=[{\"name\":\         


        

Answer 1

The key argument needs to be a function. operator.itemgetter(i) returns a function, but in order to add extra processing on top of that, you'll have to use a lambda. Because itemgetter returns a function, you can call the result to use it on the dictionary (which you are passing as the x in the lambda:

listsorted = sorted(XWordDict, key=lambda x: int(operator.itemgetter("pos")(x)))
listsorted
Out[16]: 
[{'name': 'ABC', 'pos': '1'},
 {'name': 'DEF', 'pos': '2'},
 {'name': 'GHI', 'pos': '10'}]

That said, itemgetter might be an overly complex solution here, you can just do:

listsorted = sorted(XWordDict, key=lambda x: int(x['pos']))