Why this C program throws segmentation fault at runtime?

Question

I\'m declaring character array as char* string. And then I declare other pointer which again refer to original string, then when I\'m going to change any thing on that string, a

Answer 1

you try to modify the string literal. It is an Undefined Behavoiur and everything may happen including the segfault.

from the C standard what is an UB:

—The program attempts to modify a string literal (6.4.5).