Wrong number of parameters to printf leads to strange results

Question

#include 

int main() {
   int i=10,j=20;
   printf(\"%d%d%d\",i,j);
   printf(\"%d\",i,j); 
   return 0;
}

Using the Turbo C compiler,

Answer 1

printf("%d%d%d",i,j); =>

you are telling printf to print three integer, but you provide just three, so printf prints some garbage from the stack. the other:

printf("%d",i,j);

is supposed to take just one integer, but you are passing two. The C language does not guard against such errors, and what's happen is completely undefined, so to explain how you see exactly these outputs is difficult unless you know your compiler internal, and not so useful since that code is wrong and expected to fail.