JS ES6 Correct way to filter object by array of keys

Question

I would like to take an array of objects and filter each object to only return the properties where the key matches an item in an array.

For example:

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Answer 1

You can .map each object to its entries so you can .filter out any entries which don't have a key in myKeys, and then use .fromEntries() to build up your new object like so:

const myKeys = ['key_1', 'key_3'];
const myArray = [{
    key_1: 'Some Value A',
    key_2: 'Some Other Value A',
    key_3: 'Some Final Value A',
  },
  {
    key_1: 'Some Value B',
    key_2: 'Some Other Value B',
    key_3: 'Some Final Value B',
  },
  {
    key_1: 'Some Value C',
    key_2: 'Some Other Value C',
    key_3: 'Some Final Value C',
  },
];

const res = myArray.map(obj => Object.fromEntries(Object.entries(obj).filter(([k, v]) => myKeys.includes(k))));

console.log(res);