Array Arrangement Permutation

Question

Looking for a way to sequentially find different arrangement possibilities of an array. I only care about adding them sequentially, doesn\'t need skip or shuffle values.

Answer 1

var array = ['a', 'b', 'c', 'd', 'e', 'f'];
results = [];
for (x = 1; x < array.length + 1; ++x) {
  results.push(array.slice(0, x).toString().replace(/,/g, ""))
}
//PRINT ALL RESULTS IN THE RESULTS VARIABLE
for (x = 0; x < results.length; ++x) {
  console.log(results[x])
}