select sql data order by date

Question

I have a table with a column called date, as a varchar. The contents are specifically formatted like \'March 11, 2011\'.

How can I select the results have

Answer 1

If your two dates are in variables such as $date_begin and $date_end, you could use an SQL query like the following one, to get data that's between those dates :

select *
from your_table
where date between '$date_begin' and '$date_end'

(Not sure I quite understand the question)
If you want to get the rows that correspond to the current date, you'll need to variables :

• $current ; that would be like 2011-03-20 -- which means 2011-03-20 00:00:00
• $next ; that would be like 2011-03-21 -- which means 2011-03-21 00:00:00

And you'll use a query like this one :

select *
from your_table
where date >= '$current' and date < '$next'

To select data that has its date which is greater or equal that today ; and that's before tomorrow.

In any case, try to not apply an SQL function on your date column ; don't do anything like this :

where some_function(date) >= ...

Doing this, your database engine would have to apply that function to all lines of your table, not using any index you might have on the date column -- and this will result in bad performances.