Why use SomeType[1] instead of SomeType* as last member in structs

Question

I saw in the code next statement:

SomeType someVar[1];

Later someVar is used as a pointer to SomeType. Why would one

Answer 1

If you use SomeType*, you will need a new at some point and you will thus have to delete it to avoid leaks.

Using SomeType[] allocates on the stack and the memory management will be handled for you.