I\'m working on my first homework project in a web programming class, which is to write a simple web server in Java. I\'m at the point where I have data being transmitted back a
Edit It looks to me like in the 404 situation, you're sending something like this:
HTTP/1.1 404 Not Found
Content-Type: text/html
HTTP/1.1 200 OK
Content-Length: 1234
Content-Type: text/html
...followed by the 404 page. Note the 200 line following the 404. This is because your 404 handling is calling sendFile
, which is outputting the 200 response status code. This is probably confusing the receiver.
Old answer that missed that:
An HTTP response starts with a status line followed (optionally) by a series of headers, and then (optionally) includes a response body. The status line and headers are just lines in a defined format, like (to pick a random example):
HTTP/1.0 404 Not Found
To implement your small HTTP server, I'd recommend having a read through the spec and seeing what the responses should look like. It's a bit of a conceptual leap, but they really are just lines of text returned according to an agreed format. (Well, it was a conceptual leap for me some years back, anyway. I was used to environments that over-complicated things.)
It can also be helpful to do things like this from your favorite command line:
telnet www.google.com 80
GET /thispagewontbefound
...and press Enter. You'll get something like this:
HTTP/1.0 404 Not Found
Content-Type: text/html; charset=UTF-8
X-Content-Type-Options: nosniff
Date: Sun, 12 Sep 2010 23:01:14 GMT
Server: sffe
Content-Length: 1361
X-XSS-Protection: 1; mode=block
...followed by some HTML to provide a friendly 404 page. The first line above is the status line, the rest are headers. There's a blank line between the status line/headers and the first line of content (e.g., the page).