Sequential numbers in a list haskell

Question

I am new to haskell and I was attempting a few coding problems that I previously completed for java, however the following problem has me stumped.

Basically the idea is

Answer 1

You could also do it this way:

consecutiveOnes [] = False
consecutiveOnes xs = any (== (1,1)) $ zip xs (tail xs)

If

 xs == [0,1,1,2,3,4]

Then

tail xs == [1,1,2,3,4]

Zipping them together you get a list of pairs, where each pair is an element of the list and the element after it.

zip xs (tail xs) == [(0,1),(1,1),(1,2),(2,3),(3,4)]