Assignment makes pointer without a cast

Question

I am editing a quick sort code so that the values of low, high, and middle point to an array element instead of integers.

This is my code:

#include 

        

Answer 1

Change 'split()' to return an 'int *' instead of 'int'.

Change the last line of the 'split()' function from:

return *high;

to

return high;

Perhaps this would work better:

#include 

#define N 10

void quicksort(int a[], int *low, int *high);
int *split(int a[], int *low, int *high);

int main(void)
{
    int a[N], i;
    printf("Enter %d numbers to be sorted: ", N);
    for (i=0; i= high) return;
    middle = split(a, low, high);
    quicksort(a, low, middle - 1);
    quicksort(a, middle + 1, high);
}

int *split(int a[], int *low, int *high)
{
    int part_element = *low;

    for (;;) {
        while (low < high && part_element <= *high)
            high--;
        if (low >= high) break;
        *low++ = *high;

        while (low < high && *low <= part_element)
            low++;
        if (low >= high) break;
        *high-- = *low;
    }

    *high = part_element;
    return high;
}