im trying to get my query to group rows by month and year from the assignments
table, and count the number of rows that has a certain value from the leads
You can sort of truncate your timestamps to months and use the obtained values for grouping, then derive the necessary date parts from them:
SELECT
YEAR(d_yearmonth) AS d_year,
MONTHNAME(d_yearmonth) AS d_month,
…
FROM (
SELECT
LAST_DAY(FROM_UNIXTIME(a.date_assigned)) as d_yearmonth,
…
FROM assignments AS a
LEFT JOIN leads AS l ON (l.id = a.id_lead)
WHERE id_dealership = '$id_dealership2'
GROUP BY
d_yearmonth
) AS s
ORDER BY
d_year ASC,
MONTH(d_yearmonth) ASC
Well, LAST_DAY()
doesn't really truncate a timestamp, but it does turn all the values belonging to the same month into the same value, which is basically what we need.
And I guess the counts should be related to the rows you are actually selecting, which is not what your subqueries are. Something like this might do:
…
COUNT(d.website = 'newsite.com' OR NULL) AS d_new,
/* or: COUNT(d.website) - COUNT(NULLIF(d.website, 'newsite.com')) AS d_new */
COUNT(NULLIF(d.website, 'newsite.com')) AS d_subprime
…
Here's the entire query with all the modifications mentioned:
SELECT
YEAR(d_yearmonth) AS d_year,
MONTHNAME(d_yearmonth) AS d_month,
d_new,
d_subprime
FROM (
SELECT
LAST_DAY(FROM_UNIXTIME(a.date_assigned)) as d_yearmonth,
COUNT(d.website = 'newsite.com' OR NULL) AS d_new,
COUNT(NULLIF(d.website, 'newsite.com')) AS d_subprime
FROM assignments AS a
LEFT JOIN leads AS l ON (l.id = a.id_lead)
WHERE id_dealership = '$id_dealership2'
GROUP BY
d_yearmonth
) AS s
ORDER BY
d_year ASC,
MONTH(d_yearmonth) ASC