Is there a way to make my program work with less code?

Question

I wrote the following code for a school assignment - It compiles and prints all the correct messages. But just for my own curiosity, I would like to know if my code can be shor

Answer 1

static void sigHandlers(int sig)
{
  if (sig == SIGINT)
    printf("Caught SIGINT, Existing\n");
  else if (sig == SIGUSR1)
    printf("Caught SIGUSR1\n");
  else //no need to switch since you have only 3 sig
    printf("Caught SIGUSR2\n");
  exit(EXIT_SUCCESS);
}

int main(int argc, char *argv[])
{
  struct sigaction s[4] = {0};

  s[0].sa_handler = sigHandlers;
  sigemptyset(&(s[0].sa_mask));

  memcpy(&s[1], s, sizeof(struct sigaction));
  memcpy(&s[2], s, sizeof(struct sigaction));

  sigaction(SIGUSR1, &s[0], &s[3]);
  sigaction(SIGUSR2, &s[1], &s[3]);
  sigaction(SIGINT, &s[2], &s[3]);

  kill(getpid(), SIGUSR1);
  kill(getpid(), SIGUSR2);
  kill(getpid(), SIGINT);

  return 0;
}

But I'm sure you can reduce the code with #define