passing arg 1 of `foo' from incompatible pointer type

Question

Why this shows warning:

#include
foo (const char **p)
{ 

}

int main(int argc , char **argv)
{
    foo(argv);
}

But following

Answer 1

See the C FAQ list

You can cast in order to remove warnings:

foo((const char **)argv);

But as FAQ says: the need for such a cast may indicate a deeper problem which the cast doesn't really fix.