eval(fn) and eval(arrowFn) returns different value

Question

As per the Mozilla docs in order to execute a function using eval it must be wrapped inside ( ) i.e. if you don\'t use them then it treate

Answer 1

In your example, a is declared as it's a named function. In the second case, you just write an expression which is a lambda function. See here and here.

If you want to get the same effect for fn, do

`console.log(eval("var a = function(){}"))`; //`function(){}`.