ASP.NET 3.5 C#: Best way to create and display dynamic menu with submenus

Question

I usually just create a datatable with one repeater and have all this html in my codebehind. I have not found an easy method for adding a submenu dynamically. Does anyone have

Answer 1

You can create a xslt File and Get the records from the database dynamically.

Download the Full Source Code

    
    
     

     
     
     

     

     
     
     
     
     
     
     
     
     
     
     
     

     
     
    
    

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data.SqlClient;
using System.Xml;
using System.Data;

public partial class _Default : System.Web.UI.Page
{

protected void Page_Load(object sender, EventArgs e)
 {
 if (!IsPostBack)
 {
 DataSet ds = new DataSet();
 XmlDataSource xmlDataSource = new XmlDataSource();
 xmlDataSource.ID = "xmlDataSource";
 xmlDataSource.EnableCaching = false;

string connStr = @"Data Source=.\SQLEXPRESS;AttachDbFilename=G:\Admin\WebSite28\App_Data\Database.mdf;Integrated Security=True;User Instance=True";
 using (SqlConnection conn = new SqlConnection(connStr))
 {
 string sql = "Select ID, Text,NavigateUrl,ParentID from Menu";
 SqlDataAdapter da = new SqlDataAdapter(sql, conn);
 da.Fill(ds);
 da.Dispose();
 }

 

ds.DataSetName = "Menus";
 ds.Tables[0].TableName = "Menu";
 DataRelation relation = new DataRelation("ParentChild",
 ds.Tables["Menu"].Columns["ID"],
 ds.Tables["Menu"].Columns["ParentID"],
 true);

relation.Nested = true;
 ds.Relations.Add(relation);

xmlDataSource.Data = ds.GetXml();

//Reformat the xmldatasource from the dataset to fit menu into xml format
 xmlDataSource.TransformFile = Server.MapPath("~/TransformXSLT.xsl");

//assigning the path to start read all MenuItem under MenuItems
 xmlDataSource.XPath = "MenuItems/MenuItem";

//Finally, bind the source to the Menu1 control
 Menu1.DataSource = xmlDataSource;
 Menu1.DataBind();
 }

}
}