ASSEMBLY - how to do sum between two numbers(interval)

Question

Hey guys can you help? I dont know how to do sum between two numbers For example :

first number>1

second number>5

sum w

Answer 1

proc display_interval

    push BP                 
    mov BP, SP
    mov AX, [BP+4]
    mov SP, BP
    pop BP

    print msg4
interval:    
    mov  ax, num1       ;AX = CURRENT NUMBER.
    add  suma, ax
    ;CONVERT CURRENT NUMBER TO STRING.
    call dollars        ;FILL "STR" WITH '$'.
    call number2string  ;PARAMETER = AX.

    mov  ah, 9
    mov  dx, offset str
    int  21h

    mov  ah, 9
    mov  dx, offset plus
    int  21h

    inc  num1
    mov  ax, num1
    cmp  ax, num2
    jbe  interval   ;IF AX <= NUM2


    ;BACKSPACE (DELETE LAST +).
    print back
    print equal

    call dollars        ;FILL "STR" WITH '$'.
    mov  ax, suma
    call number2string  ;PARAMETER = AX.

    mov  ah, 9
    mov  dx, offset str
    int  21h

    ;-------------------------------------------
    ;IF SUMA IS EVEN RET WILL JUMP FEW ROWS BELOW(d2)
    mov dx,0                ;dividing
    mov bl,suma
    mov ax,bx
    mov cl,2
    div cl                  ;the remainder from division stores in AH
    mov dl,ah
    add dl,48               ;48 ASCII is 0, for compare
    cmp dl,48               ;0?
    je  d2                  
                            ;dividing end
    pop ax
    mov sp,bp
    pop bp
    ret                     ;normal RET

d2: pop ax
    mov dx,583              ;number whitch it jumps from RET
    mov [bp+2],dx
    mov sp,bp
    pop bp
    ret                     ; jumping RET, if suma is even

endp