How to switch widgets in stacked widget using a button?

Question

So I have created a stacked widget with 2 pages. In the first page, I have one button \" Sign In \". In the second page, I have One button \" Logout\"

I want that, if I

Answer 1

According to the code you provide, I deduce that you used StackedWidget as a template, so the class you use fills in ui to inherit from that class.

An error that I see in your code is self.ui.StackedWidget since ui has no attribute called StackedWidget, so you should throw an exception.

Considering the above, the solution is:

from PyQt5 import QtCore, QtGui, QtWidgets


class Ui_StackedWidget(object):
    def setupUi(self, StackedWidget):
        # ...

    def retranslateUi(self, StackedWidget):
        # ...


class StackedWidget(QtWidgets.QStackedWidget):
    def __init__(self, parent=None):
        super().__init__(parent)
        self.ui = Ui_StackedWidget()
        self.ui.setupUi(self)
        self.ui.LogoutBtn.clicked.connect(lambda : self.setCurrentIndex(0))
        self.ui.pushButton.clicked.connect(lambda : self.setCurrentIndex(1))


if __name__ == '__main__':
    import sys
    app = QtWidgets.QApplication(sys.argv)
    w = StackedWidget()
    w.show()
    sys.exit(app.exec_())