Javascript Function Accepting PHP Variables

Question

I\'m drawing a complete blank why this isn\'t working. I can do it with one variable passing through, but not two. When I use actually numbers like getnt(1,2) it wo

Answer 1

If the ID and pnID are strings, enclose them with brackets like this.

  
  VIEW";
  ?>
  

If still not working, You can debug your code

1. View the source code in browser, make sure it generates correctly.

2. Put some alert messages in the javascript function. Install Firebug if you have Firefox or see

3. Javaascript console if you get any javascript errors.