I want to parse an String containing 8 hex-digits (4bytes) but i got an NumberFormatException. What is wrong here?
assertThat(Integer.parseInt(\"FFFF4C6A\",16),i
If you just want to represent that hex string as an integer (since it is 32 bits), you need to use BigInteger:
BigInteger
new BigInteger("FFFF4C6A", 16).intValue()