How do I print a letter based on the index of the string?

Question

I want to print a letter instead of the index position using the indexOf(); method. The requirement is that: Inputs a second string from the user. Outputs the character after t

Answer 1

Based on those comments

So, what you want is print the first letter based on a letter the user has input? For example, for the word Keyboard, and user inputs letter 'a' the first letter might be 'R'. Is that it? – Guerino Rodella

Yes, I have to combine both the indexOf(): method and the charAt(): method – Hussain123

The idea is get next letter based on user input letter. I'm not sure I wunderstood it, but this is my shot

  public static void main(String[] args) {

        Scanner keyboard = new Scanner(System.in);
        String phrase = "keyboard";
        String userInput = keyboard.nextLine();

        boolean notContainsInputValue = !phrase.contains(userInput);
        if (notContainsInputValue) {
            System.out.println("The input value doesn't exists");
            return;
        }

        char firstLetter = userInput.charAt(0);
        int desiredIndex = 0;
        for (int i = 0; i < phrase.length(); i++) {
            if (phrase.charAt(i) == firstLetter) {
                desiredIndex = i;
                break;
            }
        }
        System.out.println("The index for your input letter is: " + desiredIndex);
        System.out.println("Next letter based on input value is: " + phrase.charAt(desiredIndex + 1));
    }

The Output

The index for your input letter is: 5
Next letter based on input value is: r

Hope that helps you.