Java Best way to throw exception in a method

Question

I have created my own type of exception and want to implement it in a method. As of now I have written it in the following way, and it works.

public Worker remov         


        

Answer 1

1 Your code would be more efficient if you implemented Comparable and the compareTo method in Worker as follows -

@Override
public int compareTo(Object obj) {
  // identity.
  if (obj == this) {
    return 0;
  } else if (obj instanceof Worker) {
    Worker w = (Worker) obj;
    if (w.getNumber().compareTo(number) != 0) {
      return w.getNumber().compareTo(number);
    } else if (w.getLastName().compareTo(lastName) != 0) {
      return w.getLastName().compareTo(lastName);
    }
    return w.getFirstName().compareTo(firstName);
  }
  return -1;
}

And then use the SortedSet collection type (e.g. TreeSet), especially the remove method.

2 You should probably just return null. Throwing an Exception is certainly your choice, but (IMO) an unchecked Exception should be reserved for unrecoverable errors.