why cant we pass &array to function where &array[0] is possible

Question

void fun(int* array){}  


int main(){

int array[]={1,2,3};
fun(&array);----->(1)//error in this line
return 0;
}

error: cannot convert â

Answer 1

You have mismatching types.

The function expects *int (pointer to an int).

array and &array[0] is of that type, *int.

But &array is of type int(*)[3] (pointer to an array of 3 ints).