How can i return the second element in the list that starts with “b”

Question

I have this function with lists that has strings in it and I have to find the second element in this list that starts with \"b\".

for example:

second_e         


        

Answer 1

You can use the python built-in function startswith() to check the first element of the string.

lst = ["b", "a", "bb"]

# Check the first element
sample = "Sample"
print(sample.startswith("S"))
# Output : True

Now, you need to iterate through list to check each of the indices that starts with b

# Create empty list
lst_2 = []
# Loop through list
for element in lst.startswith("b"):
    # Add every element starts with b
    lst_2.append(element)
    # Print the second element which starts with b
    print(lst_2[1])