How can i return the second element in the list that starts with “b”

Question

I have this function with lists that has strings in it and I have to find the second element in this list that starts with \"b\".

for example:

second_e         


        

Answer 1

lst = ["b", "a", "bb"]

print([i for i in lst if i.startswith("b")][1])

Output:

"bb"

Or as a function:

def func(lst):
    return [i for i in lst if i.startswith("b")][1]