Finding Even Numbers In Python

Question

I have a Python assignment that is as following: \"Write a complete python program that asks a user to input two integers. The program then outputs Both Even

Answer 1

An even number is an integer which is "evenly divisible" by two. This means that if the integer is divided by 2, it yields no remainder. Zero is an even number because zero divided by two equals zero. Even numbers can be either positive or negative.

1. Use raw_input to get values from User.
2. Use type casting to convert user enter value from string to integer.
3. Use try excpet to handle valueError.
4. Use % to get remainder by dividing 2
5. Use if loop to check remainder is 0 i.e. number is even and use and operator to check remainder of tow numbers.

code:

while  1:
    try:
        no1 = int(raw_input("Enter first number:"))
        break
    except ValueError:
        print "Invalid input, enter only digit. try again"

while  1:
    try:
        no2 = int(raw_input("Enter second number:"))
        break
    except ValueError:
        print "Invalid input, enter only digit. try again"


print "Firts number is:", no1
print "Second number is:", no2

tmp1 = no1%2
tmp2 = no2%2
if tmp1==0 and tmp2==0:
    print "Both number %d, %d are even."%(no1, no2)
elif tmp1==0:
    print "Number %d is even."%(no1)
elif tmp2==0:
    print "Number %d is even."%(no2)
else:
    print "Both number %d, %d are NOT even."%(no1, no2)

Output:

vivek@vivek:~/Desktop/stackoverflow$ python 7.py
Enter first number:w
Invalid input, enter only digit. try again
Enter first number:4
Enter second number:9
Firts number is: 4
Second number is: 9
Number 4 is even.