I want to solve these equations using MATLAB and I am sure there is a non zero solution. The equations are:
0.7071*x + 0.7071*z = x
-0.5*x +
I don't think you need to use the solve
function as your equations is a system of linear equations.
Recast as a matrix equation:
Ax = B
In your case:
| -0.2929 0.0 0.7071 | | x | | 0 |
| -0.5 -0.2929 0.5 | | y | = | 0 |
| -0.5 -0.7071 -0.5 | | z | | 0 |
Use the built-in functionally of MATLAB to solve it. See e.g. MATLAB: Solution of Linear Systems of Equations.
The core of MATLAB is to solve this kind of equation.
Using FreeMat (an open-source MATLAB-like environment with a GPL license; direct download URL for Windows installer):
A = [ -0.2929 0.0 0.7071; -0.5 -0.2929 0.5; -0.5 -0.7071 -0.5 ]
B = [0.0; 0.0; 0.0]
A\B
ans =
0
0
0
So the solution is: x = 0, y = 0, z = 0
The solution can also be derived by hand. Starting from the last two equations:
-0.5*x + 0.7071*y + 0.5*z = y
-0.5*x - 0.7071*y + 0.5*z = z
0.2929*y = -0.5*x + 0.5*z
0.7071*y = -0.5*x + 0.5*z
0.2929*y = 0.7071*y
Thus y = 0.0 and:
0.7071*y = -0.5*x + 0.5*z
0 = -0.5*x + 0.5*z
0 = -0.5*x + 0.5*z
0.5*x = 0.5*z
x = z
Inserting in the first equation:
0.7071*x + 0.7071*z = x
0.7071*x + 0.7071*x = x
1.4142*x = x
Thus x = 0.0. And as x = z, then z = 0.0.