Why does my program accept one integer too many and input one too few?

Question

I\'d like to understand why the program allows me to input 3 integers when I have defined SIZE as 2. And when it returns the array it only returns two numbers NOT the three I ha

Answer 1

why the program allows me to input 3 integers

This loop runs exactly 2 times:

for (count=1;count<=SIZE;count++){
        scanf("%d\n",&myArray[count]);
    }

But as you used \n in the scanf(), this scanf() waits until you give any whitespace.

Proper Input code:

for (count=0;count

And when it returns the array it only returns two numbers

Your original output code prints first number correctly, But your second number is garbage value.

Proper Output Code:

for (count=0;count

So Full Code goes like this:

//C How to Program Exercises 2.23
#include 
#include 
#define SIZE 2

int main (void){

    int myArray[SIZE];
    int count;
    printf("Please enter 5 integers\n");
    for (count=0;count