How do I regex split by space, avoiding spaces within apostrophes?

Question

I want \"git log --format=\'(%h) %s\' --abbrev=7 HEAD\" to be split into

[
  \"git\", 
  \"log\",
  \"--format=\'(%h) %s\'\",
  \"--abbrev=7\",
  \         


        

Answer 1

I found one possible (albeit ugly) solution in python (which also works with "):

>>> import re
>>> foo = '''git log --format='(%h) %s' --foo="a b" --bar='c d' HEAD'''
>>> re.findall(r'''(\S*'[^']+'\S*|\S*"[^"]+"\S*|\S+)''', foo)
['git', 'log', "--format='(%h) %s'", '--foo="a b"', "--bar='c d'", 'HEAD']