Why does printf implicit float to int conversion not work?

Question

Please help me in understanding the following C Output:

#include
int main() {
    float x = 4.0;
    printf(\"%f\\n\",x);
    printf(\"%d\\n\",x);         


        

Answer 1

as far as i have read when we assign float to an int variable the decimal part of the variable is terminated and then assigned to the int.

Statement is correct, but to make this conversion you must cast variable you wish to convert, not just assign it to another int variable.

This causes problems also in the printf statement, since you are printing a float variable with int specifier %d without a cast.

Fix you're code like this:

printf("%d\n", (int) x);
                 ^
                 | this is the cast operation

and it will correctly print integer value 4 for variable x.