Why doesn't volatile in Java update the value of a variable?

Question

I\'ve read that "volatile" in Java allows different threads to have access to the same field and see changes the other threads has made to that field. If that\'s the c

Answer 1

volatile can make sharing safe (if atomicity of a single read or write operation is sufficient), it doesn't cause sharing.

Note that if you make d static, it is actually unspecified what value d would have, because the statement d = d + 1 is not atomic, i.e. a thread may be interrupted between reading and writing d. A synchronized block, or an AtomicInteger are the typical solutions for that.