Digital Root without loops Python

Question

def digit_sum(n):
    \'\'\'(int)->number
    Returns the sum of all the digits in the given integer, n\'\'\'
    if n<10:
        return n
    return n%10 + digit         


        

Answer 1

{def MDR(n):
    '''
    this function returns multiplicative digital root.
    '''
    count, mdr = 0, n 
    while mdr > 9:
        m, digitsMul = mdr, 1
        while m:
            m, md = divmod(m, 10)
            digitsMul *= md
        mdr = digitsMul
        count += 1
    return count, mdr}