Digital Root without loops Python

Question

def digit_sum(n):
    \'\'\'(int)->number
    Returns the sum of all the digits in the given integer, n\'\'\'
    if n<10:
        return n
    return n%10 + digit         


        

Answer 1

def droot(a):
    while a>=10:
         b =int(a/10) #other digit(s)
         c =a-(b*10)  #the rightmost digit
         a =b+c #add together
    return a

I have not seen this solution anywhere, so I thought it would be nice to share, i discovered it myself! Just 1 looping structure.