What is a good way to layer like this in pygame?

Question

I\'ve been working on a small project in pygame. It\'s an overhead 2D game, but if a player is behind an object, I need the player to be one layer behind it. If the player is in

Answer 1

I tried with this code (it most likely works)

When the red surface is behind the green the green will overlap, that's why I've kept it a little transparent. When the red overtakes it will be blitted on the green. The code is same as you did. IDK why yours doesn't work

import pygame

pygame.init()
clock = pygame.time.Clock()

screen = pygame.display.set_mode((800,600))

surface1 = pygame.Surface((50,50))
surface1.fill((255,0,0))

surface2 = pygame.Surface((50,50))
surface2.fill((0,255,0))
surface2.set_alpha(196)

surface1X = 0
surface1Y = 275

surface2X = 400
surface2Y = 275

x_change = 0
y_change = 0

speed = 2

while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()

        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_LEFT:
                x_change = -speed
            if event.key == pygame.K_RIGHT:
                x_change = speed
            if event.key == pygame.K_UP:
                y_change = -speed
            if event.key == pygame.K_DOWN:
                y_change = speed

        if event.type == pygame.KEYUP:
            if event.key == pygame.K_LEFT or event.key == pygame.K_RIGHT or event.key == pygame.K_UP or event.key == pygame.K_DOWN:
                x_change = 0
                y_change = 0

    surface1X += x_change
    surface1Y += y_change

    screen.fill((255,255,255))

    if (surface1X < surface2X):
        screen.blit(surface1, (surface1X, surface1Y))
        screen.blit(surface2, (surface2X, surface2Y))

    else:
        screen.blit(surface2, (surface2X, surface2Y))
        screen.blit(surface1, (surface1X, surface1Y))

    pygame.display.update()
    clock.tick(60)