How to filter generated Swagger JSON (yaml)

Question

I have over 5k lines long swagger.json file describing hundreds of paths and objects. I want to generate a TypeScript client (using swagger-codegen) using only a part of the end

Answer 1

I think you can do it, using task automation (grunt, gulp, shell, whatever). Basically it could be a 3 steps task:

1. get the swagger.json (or call the swagger code-gen to get the json, with something like java -jar swagger-codegen-cli-x.x.x.jar generate -i -l swagger -o GeneratedCodeSwagger )
2. remove the definitions/paths that you want to exclude and create a modified swagger.json
3. call the code-gen passing the modified json with java -jar swagger-codegen-cli-x.x.x.jar generate -i GeneratedCodeSwagger\swagger.json -l typescript-angular