One url pattern for two models in Django

Question

Is it possible to have one url pattern for two models in Django?

I have two models: Game and Category and I want one url pattern for both of these:

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Answer 1

I don't think there is a way to say that you want to continue looking through the urls from a view. You could, however, create a view which calls the correct view. I did something like this before. Something like:

class GameCategoryFactory(View):
    def dispatch(self, request, *args, **kwargs):
        game_or_category_slug = kwargs.pop('slug')

        if Category.objects.filter(name=game_or_category_slug).count() != 0:
            return CategoryView.as_view()(request, *args, **kwargs)
        elif Game.objects.filter(name=game_or_category_slug).count() != 0:
            return GameView.as_view()(request, *args, **kwargs)
        else:
            raise Http404

Of course, I am using class-based views. A function-based approach should be pretty straight-forward.