Reference initialization in C++

Question

Greetings, everyone!

Examining my own code, I came up to this interesting line:

const CString &refStr = ( CheckCondition() ) ? _T(\"foo\") : _T(\"bar         


        

Answer 1

An exception will bring you to a place where refStr isn't accessible and you can't go to a place where it is from there. A goto won't be able to get out of CheckCondition() if it is a function, and you won't be able to use a goto if it is a macro. A longjmp() will have the same effect as an exception: you'll go to a place where refStr isn't accessible.