Using regex to remove all text after the last number in a string

Question

Sample Text

1234 Main St Smallville, KS 92348Small County 

Should yield:

1234 Main St Smallville, KS 92348

Sa

Answer 1

You can use greedy .* before \d+ to make sure to match upto last digits:

>>> print re.findall(r'^(.*\d+).*$', address)[0]
1234 Main St Smallville, KS 92348

Regex Demo