My code looks like this so far:
public class ThreeSort {
public static void main(String[] args) {
int num1 = Integer.parseInt(args[0]);
int
in this case there is a simple algorithm for it:
mid = Math.max(Math.min(num1,num2), Math.min(Math.max(num1,num2),num3));
Also as the operator ^
denotes bitwise xor
. so another way is:
mid=num1^num2^num3^max^min;
EXAMPLE:
public static void main(String[] args) {
System.out.println(mid(70, 3, 10));
}
static int mid(int a, int b, int c) {
int mx = Math.max(Math.max(a, b), c);
int mn = Math.min(Math.min(a, b), c);
int md = a ^ b ^ c ^ mx ^ mn;
return md;
}
OUTPUT: 10.
Also as OldCurmudgeon said below you can calculate the mid
with below formula:
int mid = num1 + num2 + num3 - min - max;