Split string based on regex but keep delimiters

Question

I\'m trying to split a string using a variety of characters as delimiters and also keep those delimiters in their own array index. For example say I want to split the string:

Answer 1

Well, you can use lookaround to split at points between characters without consuming the delimiters:

(?<=[()>*-;\s])|(?=[()>*-;\s])

This will create a split point before and after each delimiter character. You might need to remove superfluous whitespace elements from the resulting array, though.

Quick PowerShell test (| marks the split points):

PS Home:\> 'if (x>1) return x * fact(x-1);' -split '(?<=[()>*-;\s])|(?=[()>*-;\s])' -join '|'
if| |(|x|>|1|)| |return| |x| |*| |fact|(|x|-|1|)|;|