How does Javascript execute code when duplicate named functions are declared?

Question

I\'m trying to understand why declaring a duplicate function after a statement has executed affects it.

It\'s as if JavaScript is reading ALL functions first,

Answer 1

It's called Hoisting, all declarative functions and variable declarations are moved up, though undefined, at compilation.

http://code.tutsplus.com/tutorials/javascript-hoisting-explained--net-15092

http://bonsaiden.github.io/JavaScript-Garden/#function.scopes

declarative function are functions like

function name(){...}