Find last non-zero element's index in pandas series

Question

I\'d like to find the index of last non-zero element in pandas series. I can do it with a loop:

ilast = 0
for i in mySeries.index:
    if abs(mySeries[i]) > 0         


        

Answer 1

I might just write s[s != 0].index[-1], e.g.

>>> s = pd.Series([0,1,2,3,0,4,0],index=range(7,14))
>>> s
7     0
8     1
9     2
10    3
11    0
12    4
13    0
dtype: int64
>>> s[s != 0].index[-1]
12

Originally I thought using nonzero would make things simpler, but the best I could come up with was

>>> s.index[s.nonzero()[0][-1]]
12

which is a lot faster (30+ times faster) for this example but I don't like the look of it.. YMMV.