I\'d like to define a function that takes a promise, and returns an identical promise, except that the returned promises resolves an arbitrary timeout; my code looks something l
I think you're on the right track, but that you're missing some details - specifically your delayedPromise
won't invoke any subsequent callbacks with the same context and parameters as the original promise.
Try this, instead:
function delayedPromise(promise, timeout) {
var d = $.Deferred();
promise.then(function () {
var ctx = this;
var args = [].slice.call(arguments, 0);
setTimeout(function () {
d.resolveWith(ctx, args);
}, timeout);
}, function () {
var ctx = this;
var args = [].slice.call(arguments, 0);
setTimeout(function () {
d.rejectWith(ctx, args);
}, timeout);
});
return d.promise();
}
where the d.resolveWith()
and d.rejectWith
calls are necessary to preserve the aforementioned context and parameters.
Note that you progress
notifications are not delayed with this method, although those don't necessarily make any sense in this context.
Similarly, if you actually want rejected promises to resolve immediately (without delay) then remove the second function
passed to .then
.